A question regarding the control of AC signals using a DC bias ?

if we have a circuit that consists of an AC power supply that gives + - 10 volts and a battery that gives 5 volts and a resistor of 5 ohms and the output of the circuit is shunt connected to the resistor .


how will the output of the circuit look like ?


please explainA question regarding the control of AC signals using a DC bias ?
I'm guessing that the AC supply is in parallel (shunt) with the battery, and the resistor is connected also in parallel.





This is a very bad idea, as the two supplies would short each other out and blow fuses or have the supply go up in smoke. The battery would certainly be damaged and go up in flames.








So perhaps the supply and battery are in series, and the resistor also in series, the three forming a series circuit. This makes more sense.





Also assuming the AC supply is supplying an AC wave form of 卤10 volts peak or 20 volts P-P.





When you add in the 5 volt battery, the voltages will add and you will have an AC waveform offset by 5 volts, that is, swinging between 鈥? volts and + 15 volts. Or, between 鈥?5 volts and + 5 volts, depending on the polarity of the battery and your reference. This same voltage will appear across the resistor load.








edit ';control of AC signals using a DC bias'; This part of your question doesn't relate to the rest of the question. What are you trying to control?





.A question regarding the control of AC signals using a DC bias ?
See Link for my addition of the DC and AC


waveforms that relate to your question.








http://i657.photobucket.com/albums/uu297鈥?/a>
You can put an AC power supply in series with a battery with a ';shunt';, as you call it, consisting of a resistor and a transformer. I'm guessing the transformer has the proper hysteresis that is compatible with a battery. This might also be called a dampening circuit or a modulating circuit if your looking for something in an electronics search. The resistor should be 220k ohms which is about the same as the secondary on a power transformer or 110 input and 3 to 12 output type transformer. I use this for charging batteries, if I don't have a proper charger with the blinking leds, by putting a battery on the primary of the transformer used in the ';shunt'; part. Hope that helps.